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Wednesday, 25 December 2013
Penta-denominator Integrals
Wednesday, 9 October 2013
Would Korean Grand Prix Persist?
Well, first of all, in gratitude for Korean governors spending their money to maintain the Grand Prix, I will mention some good things, some of which were not expected at all before getting into the place. As a Korean, the date was perfect to enjoy whole week for a spectator and also for the drivers. Most drivers love to stay in Japan than Korean countryside, so they usually got back to Japan after the Korean Grand Prix. As Japan and Korea schedule has been changed, there is no need to zigzag travel. They may just go to Korea for the short weekend, and go to Japan and stay for the rest until the next Grand Prix. For a spectator, Thursday was holiday in Korea, so if somehow took vacation on Friday, one could enjoy the whole weekend.
Also, what I was worried about was accommodations. I heard that the Grand Prix running committee controlled price of the accommodations in the area after the first year's merciless increase of the room charge. "Motels" are usually used for couples to stay out 'for a moment from their family' though many businessmen use to stay over nights. Thus, you can see the price for 'stay (1hr)' and 'night', both of which are still very cheap. So, inversely, I worried that my room can be borrowed for others to 'stay' during day 'as happened in the first year to the Italian writer' if the price is that cheap. I only stayed one night near the Mokpo station, the cheapest place, but the bed was normally clean, and it seems dirty behind the chests, but no way to be problem for hygiene. And, every morning, several maids came to clean with only $30 a night. So, you don't have to worry about Mokpo city. Transportation is little bit uncomfortable as small city, but most of things are there.
Now, I want to mention about the things. When I went to the circuit to spectate the Friday session, I saw many school kids for field trip, as mentioned by McKenzie. If you did not grow up in Korea, you may just think it as just a 'school trip' maybe decided by school headmaster. However, I know what's behind. If there is something 'patriotic' (or something by government) not making profit, they bring students (and purchased by school). This is pushing sales. Tradition from military dictatorship. I was also mobilised to see a terrible movie about Taekwondo, the producer of which made terrible box-office failure. There were all students from 3 middle schools in the area i.e. all students in my town. It seems they (i.e. governors maybe) doing this for every students every school in Korea for every other day, showing their terrible movie to the student and take money from the school or the government whatever. Of course, finally the movie failed and the producer seems to be bankrupt. The point is, the Korean Grand Prix is held by the local government, and the government thought that the ticket will not be sold so well, so pushed to the students. That's what I see from my experience. But, what's point of that? The debt of the government was not sold to the spectator and circulating inside the government. And, the students pushed to here may not know about the Grand Prix so they just went back after just 30 minutes. They, the students, were just interested in chatting each other, eating something, and to avoid sunlight. Chatting was definitely impossible because of the 'noise'. Even some of them were without earplugs, while most teachers brought earplugs for their students. So, I saw it as compulsory mobilisation -- pity for those who were not interested in -- which is also pity for those who could not buy tickets because of the occupancy by the students.
But, still, I have to mention that, including those 'education', the effort to advertise by the promoter seems making some success in Korea. F1 fans definitely increasing after the Grand Prix. Most of the Korean fans now are since the first Korean Grand Prix. Some are even since the last year's Grand Prix. Most Korean feels excitement about speed so some of them makes trouble on the public roads. Grand Prix definitely showed people about motorsports and led people to circuits. Grand Prix is leading to make motorsport tradition in Korea as the promoter wished.
Also, the boring Tilke's circuit also make excitement every year. I thought the circuit layout is very boring at the first time. Sector 1, long straights and stops, is definitely boring, but double apex turn, the complex of the last turns (14, 15, 16, 17 & 18), and the turn 1&2 are the masterpiece. "14, 15, 16, 17 & 18" shows the characteristic, and turn 1&2 and the dangerous pit exit give such excitement.
The problem is that the promoter seems to know nothing about what they are doing. Fans were increased and enthusiastic enough, but those hard-headed government officers has no idea about the details of the Grand Prix and tough security men are pushing people so I felt offended all the week. Those green guys have no interest of Grand Prix, don't know who are coming, just interested in controlling people and going home earlier. They insulted people taking picture of the garage after the podium, and pushed people out of the stand to see their local star 'SISTAR'. It seems only 3 people succeed to make through the security and stay on the track after the security guys left, those who shot by the Ted's notes. I wish that they should hire someone understanding at least 'terms and conditions' of the event. i.e. about what's the right of spectators, what's the obligation of them.
So, the reality is that the promoter pushing enthusiastic people out and filling with mobilised people which are good to control. They definitely don't know that why Korean Grand Prix is not popular. They are killing atmosphere. What they should do is not to cover up contract violation of Korean Broadcasting. (MBC did not broadcasted most Grand Prix every year which is violation of contract) They just should not kill fans. In that view, this year's Grand Prix was worst ever, and I don't think I want to go ever again.
Tuesday, 1 October 2013
#f1 #f1kr Weather analysis concerning effect of typhoon appearing this week
Today, a typhoon occured in Malaysia, proceeding north toward Korea. In 4 days, it is expected to reach Okinawa. Apparently, it will not pour significant amount of rain on the peninsula this week, with this speed.
I will discuss about indirect effect of this storm during the race session. It is good to be informed that the typhoon will not reach to the spot, but it does not mean that we can do as usual.
During the session, local weather forecast is provided, as you may have seen on the television. This pitwall warning system is basically based on the measurements. Korea is in the eastern cost of the continent, so in the Westerlies area. Basically, winds blows from the west, and every clouds and meteorology flows from the west to the east. "Shower in 10min" alert comes from the actual cloud 10 minutes away to the west from the area.
However, any storm in the northern hemisphere spins counterclockwise. It means, as this typhoon is in the south from the spot, the wind from the typhoon may blows westward, which is opposite to the tendency. This can make weather flow unexpectable and even make small storm.
The result is: no local weather forecast, no expectation of wind direction so downforce may be affected. Of course, we do not know how big it will be so it may not affect so much, except it will just hit the spot after the race.
Typhoon may affect directly from next Tuesday. I know that most teams will pack up on the race day and leave to Seoul. However, it could be affected if the storm speeds up.
I hope that there be no disaster, but storm effect could give more fun. So, it is sad that the hit is in the next week.
Saturday, 28 September 2013
Korean Grand Prix Statistics
Winner | 2010 | 2011 | 2012 |
Qualifying | Vettel 1:35.585 | Hamilton 1:35.820 | Webber 1:37.242 |
Race | Alonso | Vettel | Vettel |
- In 2012, blown diffuser and off-zone DRS during qualifying have been restricted, which slowed 2 seconds in qualifying. Get focused how people take potentials of 2013 cars.
- Pole sitter never won in this circuit. In 2010, Red Bull front row did not finish because of mechanical failure. In the Vettel’s year, 2011, Vettel simply switched his place with Hamilton from 2nd. So did in 2012.
- Thus, Vettel’s dominance has been pretty much significant in this circuit. Also, since 2011, constructor’s championship order just appeared in the result of the race. With this tendency, Alonso is highly possible to be 2nd of 3th, while Vettel takes 1st.
Thursday, 26 September 2013
이번 여행 준비 목록
1. 영상장비
- 카메라
- 카메라 배터리
- SD카드
- 카메라 배터리 충전기 (일체형)
- 110v/220v 어댑터
- 카메라 USB 케이블 (USB Mini B to USB Standard A)
- 삼각대
- 아이폰
- 애플 5W 충전기 (USB A female output)
- 라이트닝-USB 케이블
- 아이패드
- 10W 충전기 (USB A female output)
- 20핀(아이팟)-USB 케이블
- 보조배터리
- 보조배터리용 USB A Male - 3-phi female; 3-phi male - USB Micro B 충전케이블
- 검은색 USB 5W 충전기 (번들, 안정성 확인불가, USB A female output)
- 와이브로 에그
- 전용 충전기 (10W USB Micro-B male output, 흰색)
- 인이어 이어폰
- 3단 우산
- 우비
- 상/하의 및 가방 방수 연구 필요
- 지퍼랩
- 아이패드/아이폰 용도
- 속옷 하의 5벌
- 점퍼 1벌
- 양말 5켤레
- 긴팔 티셔츠 3벌
- 동계 체육복 1벌
- 하계 체육복 1벌
Saturday, 14 September 2013
Suggestion of new display standards for tablets
However, considering that a tablet is more used to see books and such things compared to phones, standard paper size is more considerable, which is invented by Germans.
If we express this ratio sqrt(2):1 into 16:x form, the ratio is 16:11. So here we may define new ratio 16:11. We may now have old 16:12, new 16:11, obsolete 16:10, and HD 16:9 now.
Now, I think that a tablet should be at least bigger than iPad, and natively support HD video. Thus, one dimension should be 1920 pixels.
Best dimensions met this criteria are: 10.990 inch display with 212 dpi. 1920x1320 pixels. 230.04 mm x 158.15 mm.
Bezels will be less than 11 mm considering iPad mini and new iPad.
Albertus Liberius. All rights reserved. Contact with Google talks.
Friday, 23 August 2013
Formula One 2013/2014 Technical Regulation Comparison
Formula One 2014 Technical Regulation Additions Review
3.4.1. Bodywork width ahead of the front wheel centre line must not exceed 1650mm.This gives the width limit of the front wing. Current front wings may have 1800mm width. (http://www.f1technical.net/articles/11634) Now, 75mm from each side may be taken, which is corresponding to some part of the endplate. This may bring less efficiency of the front wing as the area is shrunken. However,
3.7.5. Ahead of the front wheel centre line and between 750mm and 825mm(originally 840mm) from the car centre line there must be bodywork with a projected area of no less than 95,000mm2 in side view.This gives more freedom to the shape of the wing. So, FIA definitely want more narrow but larger and more complex front wings.
Moreover,
3.7.5. Any intersection of this bodywork with a lateral vertical plane or a horizontal plane must form one continuous line.this term means that no many small wings are approved. There should be single front wing.
Thursday, 2 May 2013
Possibility of Charge Addition to the Reissner-Nordstrom Black Hole
The Reissner-Nordstrom black hole has background field of metric
\[g_{\mu\nu} = \mathrm{diag}\left\{-\left(1-\frac{r_s}{r} + \frac{r_Q^2}{r^2}\right),\,\left(1-\frac{r_s}{r} + \frac{r_Q^2}{r^2}\right)^{-1},\,r^2,\,r^2\sin^2\theta\right\}\]
where
\[r_s = 2GM;\;\; r_Q^2 = \frac{GQ^2}{4\pi}\]
and of electromagnetic field
\[A_t = \frac{Q}{4\pi r}\]
Then, the geodesic is determined by the action
\[S=\int d\tau\left[-m\sqrt{(1-\frac{r_s}{r} + \frac{r_Q^2}{r^2})\dot{t}^2 - \frac{1}{1-\frac{r_s}{r} + \frac{r_Q^2}{r^2}}\dot{r}^2 - r^2\dot{\phi}^2}+\frac{qQ}{4\pi r} \dot{t}\right]\]
assuming the motion is on the plane \(\theta=\frac{\pi}{2}\),
where the normalisation of the proper time is determined by
\[\sqrt{\cdots} \equiv \sqrt{(1-\frac{r_s}{r} + \frac{r_Q^2}{r^2})\dot{t}^2 - \frac{1}{1-\frac{r_s}{r} + \frac{r_Q^2}{r^2}}\dot{r}^2 - r^2\dot{\phi}^2}=1\]
We may, first, obtain the equation of motion in angle.
\[\frac{\delta S}{\delta \phi} = -\frac{d}{d\tau} \frac{mr^2\dot{\phi}}{\sqrt{\cdots}} = -\frac{d}{d\tau} mr^2\dot{\phi}=0\]
So, we have found a constant of motion, angular momentum, which should be defined as
\[L\equiv m r^2\dot{\phi}\]
Now, we may take variation in direction of time.
\[\frac{\delta S}{\delta t} = -\frac{d}{d\tau} \left[\frac{-m () \dot{t}}{\sqrt{\cdots}}+\frac{qQ}{4\pi r}\right] = -\frac{d}{d\tau} \left[-m () \dot{t}+\frac{qQ}{4\pi r}\right] = 0\]
with the shorten expression
\[() \equiv \left(1-\frac{r_s}{r} + \frac{r_Q^2}{r^2}\right)\]
This equation of motion is also cyclic so we may define the constant of motion
\[E = -m () \dot{t}+\frac{qQ}{4\pi r}\]
The only remaining equation of equation is related to \(r\), but we may alternate the equation to the normalisation condition, conserving the degree of freedom.
\[1= \cdots = () \dot{t}^2 - ()^{-1} \dot{r}^2 - r^2 \dot{\phi}^2 = \frac{1}{m^2 ()}\left(\frac{qQ}{4\pi r} -E\right)^2-()^{-1} \dot{r}^2-\frac{L^2}{m^2r^2} \]
We may manipulate the equation as similar to the classical mechanics.
\[\frac{1}{2}m \dot{r}^2 + \frac{L^2}{2mr^2}\left(1-\frac{r_s}{r}+\frac{r_Q^2}{r^2}\right) - \frac{1}{2m}\frac{q^2Q^2}{16\pi^2r^2} + \frac{1}{m} \frac{qQE}{4\pi r} = \frac{E^2}{2m}-\frac{m}{2}()\]
By special relativity, you may find \(\frac{1}{2}m \dot{x}^2 = \frac{E^2}{2m}-\frac{m}{2}\) where \(E\) is the total energy of a particle, so \(E\) is the asymtotic energy of the test particle, in this problem.
Thus, this equation is in analogy to the energy conservation law in classical mechanics.
To simplify the situation and ease to enter the black hole, we may consider the situation \(L=0\).
Then, this seems to be a system with potential \(V(r) = -\frac{q^2Q^2}{32\pi^2 m r^2}+\frac{qQE}{4\pi mr}\), but this term itself contains the total energy \(E\) so we have to consider more carefully. First, from the shape of the potential, we may guess that the test particle may fall to the centre if the particle just overcome the threshold. i.e. \(V(r) = \frac{E^2}{2m}-\frac{m}{2}\) should have no solution. However, the solution is \[ r = \frac{qQ}{4\pi (E\mp m)}\]which always exists, considering the absolute condition \(E\geq m\). Thus, the particle always bounce back to the infinity at the outer critical point \[r = \frac{qQ}{4\pi (E-m)}\]
Not to enter inside of the horizon, the criterion is thus
\[\frac{E-m}{q} \leq \frac{\sqrt{M^2 + \frac{Q^2}{4\pi G}}-M}{Q}\]
For further study: I'll note here http://arxiv.org/abs/1304.6474 which is a part of my project here. I may list tasks to determine charged black hole stability and radiation
*particle generation in strong electric field
*decay rate of particle-anti-particle pair in terms of gas density
Tuesday, 26 February 2013
갤럭시 넥서스 반납
안드로이드가 아무리 버터프로젝트를 해도 움직이는거보면 역시 iOS랑 짜임새가 다르더군요. 그렇다고 이제와서 다시 짤수도 없고 다른 OS를 만들수도 없으니... 젤 깔끔한 iOS가 젤 나은것 같습니다. 물론 Windows Phone이 좀 깔끔하게 되면 엄청난 경쟁력을 가질수도...
아, 제가 깔끔하다는 기준은 Sync 시스템입니다. UI도 깔끔해야되고, Sync하다가 날려먹지 않는 신뢰성과 version control은 필수고요. 여러 서비스의 계통이 간단해서 내가 원하는 서비스를 쓸때 한가지 옵션만이 존재하도록 하는겁니다. 사진공유서비스가 두개는 필요없잖아요. 근데 윈도는 기본사진뷰어도 두개고 (Live포함) SkyDrive 앨범..은 좋지만 온라인에서 바로 태그편집이 안되는게 가장큰 단점이네요. 무엇보다 '앨범'이 아니라 '폴더'라는 생각이 들게하는점이 좀 아쉬워요. 물론 파일이름 고칠수 있는건 좋지만.
現状を踏まえていく書き込み
Sunday, 17 February 2013
How to put USIM into iPhone
Every Internet post suggested to push hard into the pinhole to open the SIM tray, but it is wrong. Also, some says about "downside" but I didn't understand it, until I saw a movie clip on YouTube.
To open the tray, put the pin in the hole, and tilt to frontside, to make the tip push the far side from you. Now you can see that the tray pops out. You don't have to push any hard.
Friday, 18 January 2013
4-D Clifford Algebra with (-1,1,1,1) signature
Dirac Basis: \[\gamma^0=\begin{bmatrix}i&0\\0&-i\end{bmatrix};\; \gamma^i=\begin{bmatrix}0&\sigma^i\\\sigma^i&0\end{bmatrix}\]
Majorana Basis: \[\gamma^0=\begin{bmatrix}0&i\sigma^2\\i\sigma^2&0\end{bmatrix};\; \gamma^1=\begin{bmatrix}-\sigma^3&0\\0&-\sigma^3\end{bmatrix};\; \gamma^2=\begin{bmatrix}0&-i\sigma^2\\i\sigma^2&0\end{bmatrix};\; \gamma^3=\begin{bmatrix}\sigma^1&0\\0&\sigma^1\end{bmatrix};\;\]
\[\gamma^\mu_{\text{Dirac}}=\begin{bmatrix}\frac{1}{\sqrt{2}}&\frac{i}{\sqrt{2}}\\\frac{i}{\sqrt{2}}&\frac{1}{\sqrt{2}}\end{bmatrix}\gamma^\mu_{\text{Weyl}}\begin{bmatrix}\frac{1}{\sqrt{2}}&\frac{i}{\sqrt{2}}\\\frac{i}{\sqrt{2}}&\frac{1}{\sqrt{2}}\end{bmatrix}^{-1}\]