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Wednesday, 25 December 2013
Penta-denominator Integrals
∫
d
d
k
(
2
π
)
d
d
d
l
(
2
π
)
d
1
k
2
(
k
−
p
)
2
l
2
(
l
−
p
)
2
(
k
−
l
)
2
=
0
,
0
F
0
(
d
)
(
p
2
)
d
−
5
∫
d
d
k
(
2
π
)
d
d
d
l
(
2
π
)
d
k
μ
k
2
(
k
−
p
)
2
l
2
(
l
−
p
)
2
(
k
−
l
)
2
=
1
,
0
F
0
(
d
)
p
μ
(
p
2
)
d
−
5
∫
d
d
k
(
2
π
)
d
d
d
l
(
2
π
)
d
k
μ
k
ν
k
2
(
k
−
p
)
2
l
2
(
l
−
p
)
2
(
k
−
l
)
2
=
2
,
0
F
0
(
d
)
p
μ
p
ν
(
p
2
)
d
−
5
+
2
,
0
F
1
(
d
)
δ
^
μ
ν
(
p
2
)
d
−
4
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